FizzBuzz without IF in 89 bytes.
A solution that requires only 89 characters and uses no if-statements is this one:
for n in range(1,101): y=[[n,"Buzz"],["Fizz","FizzBuzz"]] print(y[n%3<1][n%5<1])
FizzBuzz is a simple coding exercise: Write a program that prints the numbers from 1 (including) to 100 (including) and whenever i) the number is divisible by 15, print “FizzBuzz” instead, ii) the number is divisible by 3 but not 15, print “Fizz”, and iii) the number is divisible by 5 but not 15, print “Buzz”.
A slightly more readable version of the answer above is given here:
for n in range(1,101): answer=[[n , "Buzz"], ["Fizz", "FizzBuzz"]] print(answer[n%3==0][n%5==0])
Instead of using the two (or three) if-statements for the most simple solution, we access a matrix via the modulo check. Also, checking
n%3<1 is equivalent to checking
n%3==0, but saves a character.
The solution is especially nice, because it is not only short but also readable.